When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 5c = 3c + 5x - 1 for c in terms of x.
| x + \(\frac{3}{5}\) | |
| 1\(\frac{1}{13}\)x - \(\frac{2}{13}\) | |
| 3\(\frac{1}{4}\)x - 1 | |
| x - 1 |