When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6b + 2b = b - z + 6 for b in terms of z.
| -\(\frac{3}{5}\)z + 1\(\frac{1}{5}\) | |
| -\(\frac{6}{7}\)z - \(\frac{1}{7}\) | |
| -\(\frac{1}{12}\)z - \(\frac{1}{6}\) | |
| 1\(\frac{4}{9}\)z - \(\frac{2}{3}\) |