When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -2c + 4c = c - 8x + 2 for c in terms of x.
| x + 3 | |
| -\(\frac{1}{4}\)x + \(\frac{5}{8}\) | |
| 4x - \(\frac{2}{3}\) | |
| \(\frac{2}{3}\)x - \(\frac{2}{3}\) |