ASVAB Math Knowledge Practice Test 513584 Results

Your Results Global Average
Questions 5 5
Correct 0 2.91
Score 0% 58%

Review

1

Simplify (2a)(7ab) + (5a2)(6b).

65% Answer Correctly
-16a2b
16a2b
16ab2
44a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(2a)(7ab) + (5a2)(6b)
(2 x 7)(a x a x b) + (5 x 6)(a2 x b)
(14)(a1+1 x b) + (30)(a2b)
14a2b + 30a2b
44a2b


2

Solve -7b + 8b = -3b + 5z + 6 for b in terms of z.

34% Answer Correctly
\(\frac{3}{4}\)z - 1\(\frac{1}{2}\)
1\(\frac{1}{7}\)z - \(\frac{6}{7}\)
-9z - 3
\(\frac{1}{2}\)z - 2\(\frac{1}{2}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

-7b + 8z = -3b + 5z + 6
-7b = -3b + 5z + 6 - 8z
-7b + 3b = 5z + 6 - 8z
-4b = -3z + 6
b = \( \frac{-3z + 6}{-4} \)
b = \( \frac{-3z}{-4} \) + \( \frac{6}{-4} \)
b = \(\frac{3}{4}\)z - 1\(\frac{1}{2}\)


3

A cylinder with a radius (r) and a height (h) has a surface area of:

54% Answer Correctly

π r2h

π r2h2

4π r2

2(π r2) + 2π rh


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


4

Simplify (3a)(9ab) - (3a2)(9b).

62% Answer Correctly
144ab2
54ab2
0a2b
b2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(3a)(9ab) - (3a2)(9b)
(3 x 9)(a x a x b) - (3 x 9)(a2 x b)
(27)(a1+1 x b) - (27)(a2b)
27a2b - 27a2b
0a2b


5

What is 2a2 - 2a2?

74% Answer Correctly
4
4a2
0a2
4a4

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

2a2 - 2a2 = 0a2