ASVAB Math Knowledge Practice Test 513584

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve b - 7b = 6b - 5z + 6 for b in terms of z.

-\(\frac{2}{5}\)z - 1\(\frac{1}{5}\)
\(\frac{6}{13}\)z + \(\frac{9}{13}\)
-1\(\frac{4}{9}\)z - \(\frac{2}{9}\)
-2z + 4