| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.60 |
| Score | 0% | 52% |
Factor y2 + 13y + 36
| (y - 4)(y + 9) | |
| (y - 4)(y - 9) | |
| (y + 4)(y - 9) | |
| (y + 4)(y + 9) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 36 as well and sum (Inside, Outside) to equal 13. For this problem, those two numbers are 4 and 9. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 + 13y + 36
y2 + (4 + 9)y + (4 x 9)
(y + 4)(y + 9)
On this circle, a line segment connecting point A to point D is called:
circumference |
|
radius |
|
chord |
|
diameter |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
supplementary, vertical |
|
obtuse, acute |
|
vertical, supplementary |
|
acute, obtuse |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).
Solve for b:
-9b + 9 = 6 - 2b
| \(\frac{1}{2}\) | |
| \(\frac{3}{8}\) | |
| \(\frac{4}{5}\) | |
| \(\frac{3}{7}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-9b + 9 = 6 - 2b
-9b = 6 - 2b - 9
-9b + 2b = 6 - 9
-7b = -3
b = \( \frac{-3}{-7} \)
b = \(\frac{3}{7}\)
The endpoints of this line segment are at (-2, -2) and (2, 0). What is the slope-intercept equation for this line?
| y = -\(\frac{1}{2}\)x + 4 | |
| y = 3x + 2 | |
| y = 2x + 3 | |
| y = \(\frac{1}{2}\)x - 1 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -2) and (2, 0) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(0.0) - (-2.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)Plugging these values into the slope-intercept equation:
y = \(\frac{1}{2}\)x - 1