ASVAB Math Knowledge Practice Test 517369

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -2b + 6b = b - 5y + 5 for b in terms of y.

3\(\frac{2}{3}\)y - 1\(\frac{2}{3}\)
-\(\frac{1}{7}\)y + \(\frac{5}{7}\)
-1\(\frac{2}{7}\)y - 1\(\frac{1}{7}\)
\(\frac{1}{2}\)y + 1\(\frac{1}{6}\)