ASVAB Math Knowledge Practice Test 517723

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 9a - 3a = 6a + 4x - 2 for a in terms of x.

\(\frac{9}{14}\)x - \(\frac{9}{14}\)
1\(\frac{1}{5}\)x - 1\(\frac{2}{5}\)
-3\(\frac{1}{2}\)x - 2\(\frac{1}{2}\)
2\(\frac{1}{3}\)x - \(\frac{2}{3}\)