When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3b + 2b = 9b - 5z + 2 for b in terms of z.
| \(\frac{1}{2}\)z + 1\(\frac{1}{4}\) | |
| 1\(\frac{1}{6}\)z - \(\frac{1}{3}\) | |
| 1\(\frac{1}{3}\)z - 1\(\frac{1}{6}\) | |
| -\(\frac{8}{15}\)z + \(\frac{1}{5}\) |