| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.78 |
| Score | 0% | 56% |
What is 7a8 + 5a8?
| 12 | |
| a816 | |
| 35a16 | |
| 12a8 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
7a8 + 5a8 = 12a8
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h |
|
2(π r2) + 2π rh |
|
4π r2 |
|
π r2h2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Solve for y:
y2 + 9y + 22 = -y + 1
| -4 or -9 | |
| 8 or -7 | |
| 7 or 3 | |
| -3 or -7 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
y2 + 9y + 22 = -y + 1
y2 + 9y + 22 - 1 = -y
y2 + 9y + y + 21 = 0
y2 + 10y + 21 = 0
Next, factor the quadratic equation:
y2 + 10y + 21 = 0
(y + 3)(y + 7) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 3) or (y + 7) must equal zero:
If (y + 3) = 0, y must equal -3
If (y + 7) = 0, y must equal -7
So the solution is that y = -3 or -7
Solve for y:
y2 - 12y + 27 = 0
| 1 or -1 | |
| 3 or 9 | |
| 7 or -5 | |
| -8 or -9 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
y2 - 12y + 27 = 0
(y - 3)(y - 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (y - 3) or (y - 9) must equal zero:
If (y - 3) = 0, y must equal 3
If (y - 9) = 0, y must equal 9
So the solution is that y = 3 or 9
If the length of AB equals the length of BD, point B __________ this line segment.
bisects |
|
trisects |
|
intersects |
|
midpoints |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.