ASVAB Math Knowledge Practice Test 519413

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2c + 9c = c - 4z - 5 for c in terms of z.

\(\frac{7}{10}\)z + \(\frac{9}{10}\)
-2\(\frac{1}{3}\)z + 2\(\frac{2}{3}\)
-13z - 5
1\(\frac{1}{11}\)z - \(\frac{7}{11}\)