When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 9c = 5c - 6z + 6 for c in terms of z.
| 7\(\frac{1}{2}\)z - 3 | |
| 2\(\frac{1}{5}\)z - \(\frac{4}{5}\) | |
| -3z + 1\(\frac{1}{2}\) | |
| \(\frac{3}{10}\)z + \(\frac{4}{5}\) |