| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.27 |
| Score | 0% | 65% |
Solve for a:
-2a + 9 < \( \frac{a}{-4} \)
| a < -\(\frac{12}{13}\) | |
| a < 5\(\frac{1}{7}\) | |
| a < -2\(\frac{4}{5}\) | |
| a < 2\(\frac{2}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-2a + 9 < \( \frac{a}{-4} \)
-4 x (-2a + 9) < a
(-4 x -2a) + (-4 x 9) < a
8a - 36 < a
8a - 36 - a < 0
8a - a < 36
7a < 36
a < \( \frac{36}{7} \)
a < 5\(\frac{1}{7}\)
If a = c = 2, b = d = 1, what is the area of this rectangle?
| 2 | |
| 40 | |
| 6 | |
| 9 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 2 x 1
a = 2
Find the value of a:
-3a + z = -7
-6a + 3z = 9
| 1\(\frac{1}{13}\) | |
| 10 | |
| -\(\frac{38}{39}\) | |
| -1\(\frac{3}{19}\) |
You need to find the value of a so solve the first equation in terms of z:
-3a + z = -7
z = -7 + 3a
then substitute the result (-7 - -3a) into the second equation:
-6a + 3(-7 + 3a) = 9
-6a + (3 x -7) + (3 x 3a) = 9
-6a - 21 + 9a = 9
-6a + 9a = 9 + 21
3a = 30
a = \( \frac{30}{3} \)
a = 10
If BD = 13 and AD = 22, AB = ?
| 9 | |
| 13 | |
| 7 | |
| 12 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDIf side x = 13cm, side y = 8cm, and side z = 6cm what is the perimeter of this triangle?
| 22cm | |
| 27cm | |
| 31cm | |
| 34cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 13cm + 8cm + 6cm = 27cm