When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c + 2c = -2c - 3z + 6 for c in terms of z.
| 2\(\frac{1}{2}\)z - 3 | |
| \(\frac{6}{13}\)z - \(\frac{2}{13}\) | |
| -\(\frac{3}{8}\)z + 1 | |
| 7z - 5 |