| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.65 |
| Score | 0% | 53% |
Which of the following statements about a parallelogram is not true?
a parallelogram is a quadrilateral |
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the perimeter of a parallelogram is the sum of the lengths of all sides |
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the area of a parallelogram is base x height |
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opposite sides and adjacent angles are equal |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).
Find the value of c:
9c + z = -8
-2c + 7z = 1
| 1\(\frac{29}{32}\) | |
| -\(\frac{57}{65}\) | |
| -1\(\frac{36}{41}\) | |
| -\(\frac{2}{5}\) |
You need to find the value of c so solve the first equation in terms of z:
9c + z = -8
z = -8 - 9c
then substitute the result (-8 - 9c) into the second equation:
-2c + 7(-8 - 9c) = 1
-2c + (7 x -8) + (7 x -9c) = 1
-2c - 56 - 63c = 1
-2c - 63c = 1 + 56
-65c = 57
c = \( \frac{57}{-65} \)
c = -\(\frac{57}{65}\)
If a = c = 5, b = d = 9, and the blue angle = 77°, what is the area of this parallelogram?
| 4 | |
| 64 | |
| 45 | |
| 8 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 5 x 9
a = 45
If the area of this square is 16, what is the length of one of the diagonals?
| 4\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| 5\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)
Which of the following is not required to define the slope-intercept equation for a line?
slope |
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y-intercept |
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x-intercept |
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\({\Delta y \over \Delta x}\) |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.