When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 4c = 8c - 3x - 2 for c in terms of x.
| \(\frac{2}{7}\)x - \(\frac{5}{7}\) | |
| 1\(\frac{2}{5}\)x + \(\frac{2}{5}\) | |
| -\(\frac{5}{6}\)x - \(\frac{1}{4}\) | |
| -\(\frac{1}{12}\)x - \(\frac{1}{6}\) |