When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -2a - 6a = -5a - 4z + 1 for a in terms of z.
| -3z + 3 | |
| \(\frac{2}{3}\)z + \(\frac{1}{3}\) | |
| 2\(\frac{1}{2}\)z - 4\(\frac{1}{2}\) | |
| -1\(\frac{1}{6}\)z - 1\(\frac{1}{3}\) |