ASVAB Math Knowledge Practice Test 522120 Results

Your Results Global Average
Questions 5 5
Correct 0 3.24
Score 0% 65%

Review

1

If angle a = 58° and angle b = 52° what is the length of angle c?

71% Answer Correctly
70°
77°
101°
78°

Solution

The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 58° - 52° = 70°


2

A coordinate grid is composed of which of the following?

91% Answer Correctly

all of these

y-axis

x-axis

origin


Solution

The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.


3

Solve for c:
6c - 2 = \( \frac{c}{5} \)

46% Answer Correctly
-\(\frac{7}{19}\)
-1\(\frac{3}{5}\)
\(\frac{7}{10}\)
\(\frac{10}{29}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

6c - 2 = \( \frac{c}{5} \)
5 x (6c - 2) = c
(5 x 6c) + (5 x -2) = c
30c - 10 = c
30c - 10 - c = 0
30c - c = 10
29c = 10
c = \( \frac{10}{29} \)
c = \(\frac{10}{29}\)


4

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

diameter

chord

radius

circumference


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

If the area of this square is 64, what is the length of one of the diagonals?

68% Answer Correctly
5\( \sqrt{2} \)
8\( \sqrt{2} \)
2\( \sqrt{2} \)
\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{64} \) = 8

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 82 + 82
c2 = 128
c = \( \sqrt{128} \) = \( \sqrt{64 x 2} \) = \( \sqrt{64} \) \( \sqrt{2} \)
c = 8\( \sqrt{2} \)