| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.47 |
| Score | 0% | 69% |
What is 9a5 + 3a5?
| 6a10 | |
| 27a10 | |
| 12a5 | |
| a510 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
9a5 + 3a5 = 12a5
Order the following types of angle from least number of degrees to most number of degrees.
right, acute, obtuse |
|
right, obtuse, acute |
|
acute, obtuse, right |
|
acute, right, obtuse |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
If the area of this square is 4, what is the length of one of the diagonals?
| 6\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{4} \) = 2
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 22 + 22
c2 = 8
c = \( \sqrt{8} \) = \( \sqrt{4 x 2} \) = \( \sqrt{4} \) \( \sqrt{2} \)
c = 2\( \sqrt{2} \)
If b = 5 and y = -3, what is the value of -8b(b - y)?
| -320 | |
| -200 | |
| -54 | |
| -90 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
-8b(b - y)
-8(5)(5 + 3)
-8(5)(8)
(-40)(8)
-320
Solve for b:
b - 9 = -5 + 7b
| 1\(\frac{4}{5}\) | |
| 2 | |
| -\(\frac{2}{3}\) | |
| 3 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
b - 9 = -5 + 7b
b = -5 + 7b + 9
b - 7b = -5 + 9
-6b = 4
b = \( \frac{4}{-6} \)
b = -\(\frac{2}{3}\)