When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3c - c = 8c - 5y - 1 for c in terms of y.
| 1\(\frac{3}{4}\)y + \(\frac{1}{4}\) | |
| -\(\frac{1}{5}\)y + \(\frac{3}{5}\) | |
| \(\frac{4}{11}\)y + \(\frac{1}{11}\) | |
| \(\frac{7}{13}\)y - \(\frac{5}{13}\) |