When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c - 6c = 6c - 4x - 3 for c in terms of x.
| -\(\frac{1}{5}\)x + \(\frac{3}{10}\) | |
| \(\frac{5}{11}\)x + \(\frac{8}{11}\) | |
| \(\frac{9}{14}\)x + \(\frac{4}{7}\) | |
| 5x - \(\frac{2}{3}\) |