ASVAB Math Knowledge Practice Test 523574 Results

Your Results Global Average
Questions 5 5
Correct 0 3.56
Score 0% 71%

Review

1

If a = 7, b = 4, c = 4, and d = 6, what is the perimeter of this quadrilateral?

88% Answer Correctly
22
21
19
15

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 7 + 4 + 4 + 6
p = 21


2

If the area of this square is 81, what is the length of one of the diagonals?

68% Answer Correctly
\( \sqrt{2} \)
3\( \sqrt{2} \)
9\( \sqrt{2} \)
5\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{81} \) = 9

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 92 + 92
c2 = 162
c = \( \sqrt{162} \) = \( \sqrt{81 x 2} \) = \( \sqrt{81} \) \( \sqrt{2} \)
c = 9\( \sqrt{2} \)


3

A coordinate grid is composed of which of the following?

88% Answer Correctly

y-axis

all of these

origin

x-axis


Solution

The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.


4

A cylinder with a radius (r) and a height (h) has a surface area of:

52% Answer Correctly

2(π r2) + 2π rh

4π r2

π r2h

π r2h2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


5

Solve for a:
-5a + 4 = -2 + 9a

58% Answer Correctly
-1
-3
2
\(\frac{3}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-5a + 4 = -2 + 9a
-5a = -2 + 9a - 4
-5a - 9a = -2 - 4
-14a = -6
a = \( \frac{-6}{-14} \)
a = \(\frac{3}{7}\)