When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c - 5c = 2c + 6z + 1 for c in terms of z.
| \(\frac{6}{7}\)z - \(\frac{3}{7}\) | |
| -\(\frac{1}{2}\)z - 2\(\frac{1}{2}\) | |
| -10z - 9 | |
| -1\(\frac{5}{6}\)z - \(\frac{1}{6}\) |