| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.47 |
| Score | 0% | 69% |
Solve for x:
7x - 9 < 7 - 8x
| x < -\(\frac{4}{5}\) | |
| x < -\(\frac{5}{7}\) | |
| x < 1\(\frac{1}{15}\) | |
| x < -1\(\frac{2}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
7x - 9 < 7 - 8x
7x < 7 - 8x + 9
7x + 8x < 7 + 9
15x < 16
x < \( \frac{16}{15} \)
x < 1\(\frac{1}{15}\)
A right angle measures:
360° |
|
45° |
|
90° |
|
180° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.
A trapezoid is a quadrilateral with one set of __________ sides.
parallel |
|
right angle |
|
equal angle |
|
equal length |
A trapezoid is a quadrilateral with one set of parallel sides.
Simplify (5a)(7ab) - (4a2)(8b).
| 144a2b | |
| 144ab2 | |
| 67a2b | |
| 3a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(5a)(7ab) - (4a2)(8b)
(5 x 7)(a x a x b) - (4 x 8)(a2 x b)
(35)(a1+1 x b) - (32)(a2b)
35a2b - 32a2b
3a2b
If the area of this square is 16, what is the length of one of the diagonals?
| \( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)