When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c + 9c = -5c - 5z + 3 for c in terms of z.
| 1\(\frac{3}{5}\)z - \(\frac{1}{5}\) | |
| 4\(\frac{2}{3}\)z - 1 | |
| \(\frac{1}{4}\)z - 1\(\frac{1}{4}\) | |
| z - 1 |