ASVAB Math Knowledge Practice Test 525615

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve c - 6c = -9c + 2y + 5 for c in terms of y.

1\(\frac{8}{9}\)y - 1
6y + 9
\(\frac{4}{5}\)y + \(\frac{1}{2}\)
-\(\frac{4}{9}\)y - \(\frac{4}{9}\)