ASVAB Math Knowledge Practice Test 526143

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -2a - 2a = -4a - 9z - 5 for a in terms of z.

-z - \(\frac{2}{9}\)
3\(\frac{1}{2}\)z + 4
-\(\frac{3}{5}\)z + \(\frac{4}{5}\)
-3\(\frac{1}{2}\)z - 2\(\frac{1}{2}\)