ASVAB Math Knowledge Practice Test 526638 Results

Your Results Global Average
Questions 5 5
Correct 0 2.98
Score 0% 60%

Review

1

Factor y2 - 3y + 2

53% Answer Correctly
(y + 2)(y + 1)
(y + 2)(y - 1)
(y - 2)(y + 1)
(y - 2)(y - 1)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 2 as well and sum (Inside, Outside) to equal -3. For this problem, those two numbers are -2 and -1. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 - 3y + 2
y2 + (-2 - 1)y + (-2 x -1)
(y - 2)(y - 1)


2

If side x = 15cm, side y = 5cm, and side z = 10cm what is the perimeter of this triangle?

84% Answer Correctly
37cm
29cm
30cm
33cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 15cm + 5cm + 10cm = 30cm


3

Simplify (5a)(2ab) - (8a2)(2b).

59% Answer Correctly
70ab2
-6a2b
26ab2
6ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(5a)(2ab) - (8a2)(2b)
(5 x 2)(a x a x b) - (8 x 2)(a2 x b)
(10)(a1+1 x b) - (16)(a2b)
10a2b - 16a2b
-6a2b


4

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

circumference

chord

radius

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

Solve for y:
y2 - 3y - 4 = 0

57% Answer Correctly
2 or 1
-1 or 4
4 or -4
7 or 2

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

y2 - 3y - 4 = 0
(y + 1)(y - 4) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 1) or (y - 4) must equal zero:

If (y + 1) = 0, y must equal -1
If (y - 4) = 0, y must equal 4

So the solution is that y = -1 or 4