| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.70 |
| Score | 0% | 54% |
Find the value of c:
-3c + y = -9
c - 3y = 1
| -\(\frac{8}{41}\) | |
| 1\(\frac{3}{13}\) | |
| -2\(\frac{13}{23}\) | |
| 3\(\frac{1}{4}\) |
You need to find the value of c so solve the first equation in terms of y:
-3c + y = -9
y = -9 + 3c
then substitute the result (-9 - -3c) into the second equation:
c - 3(-9 + 3c) = 1
c + (-3 x -9) + (-3 x 3c) = 1
c + 27 - 9c = 1
c - 9c = 1 - 27
-8c = -26
c = \( \frac{-26}{-8} \)
c = 3\(\frac{1}{4}\)
Simplify (6a)(6ab) + (7a2)(4b).
| 64a2b | |
| 132ab2 | |
| -8a2b | |
| 64ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(6a)(6ab) + (7a2)(4b)
(6 x 6)(a x a x b) + (7 x 4)(a2 x b)
(36)(a1+1 x b) + (28)(a2b)
36a2b + 28a2b
64a2b
The dimensions of this cylinder are height (h) = 1 and radius (r) = 2. What is the volume?
| 24π | |
| 80π | |
| 4π | |
| 1π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(22 x 1)
v = 4π
Solve for a:
3a - 3 < 3 - 3a
| a < 1 | |
| a < -3 | |
| a < -1 | |
| a < \(\frac{5}{8}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
3a - 3 < 3 - 3a
3a < 3 - 3a + 3
3a + 3a < 3 + 3
6a < 6
a < \( \frac{6}{6} \)
a < 1
If the length of AB equals the length of BD, point B __________ this line segment.
bisects |
|
trisects |
|
midpoints |
|
intersects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.