ASVAB Math Knowledge Practice Test 528678

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve b + 5b = 6b + 7y - 1 for b in terms of y.

-y + 2\(\frac{2}{3}\)
-3y + 4
-\(\frac{2}{13}\)y + \(\frac{4}{13}\)
-\(\frac{2}{5}\)y + \(\frac{1}{5}\)