When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 4c = 6c - 3x - 8 for c in terms of x.
| -3\(\frac{1}{2}\)x - 4 | |
| 3\(\frac{1}{2}\)x + 1\(\frac{1}{2}\) | |
| -\(\frac{1}{6}\)x - \(\frac{1}{4}\) | |
| -\(\frac{1}{4}\)x + \(\frac{1}{6}\) |