| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.93 |
| Score | 0% | 59% |
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h2 |
|
π r2h |
|
4π r2 |
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2(π r2) + 2π rh |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
Find the value of b:
5b + x = 8
8b - 9x = -1
| \(\frac{6}{7}\) | |
| -\(\frac{29}{46}\) | |
| 8\(\frac{2}{5}\) | |
| 1\(\frac{18}{53}\) |
You need to find the value of b so solve the first equation in terms of x:
5b + x = 8
x = 8 - 5b
then substitute the result (8 - 5b) into the second equation:
8b - 9(8 - 5b) = -1
8b + (-9 x 8) + (-9 x -5b) = -1
8b - 72 + 45b = -1
8b + 45b = -1 + 72
53b = 71
b = \( \frac{71}{53} \)
b = 1\(\frac{18}{53}\)
The formula for the area of a circle is which of the following?
a = π r |
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a = π d |
|
a = π r2 |
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a = π d2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
This diagram represents two parallel lines with a transversal. If d° = 151, what is the value of x°?
| 166 | |
| 169 | |
| 162 | |
| 151 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with d° = 151, the value of x° is 151.
The endpoints of this line segment are at (-2, 0) and (2, -4). What is the slope of this line?
| 1 | |
| -1 | |
| -2 | |
| -2\(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 0) and (2, -4) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-4.0) - (0.0)}{(2) - (-2)} \) = \( \frac{-4}{4} \)