| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.80 |
| Score | 0% | 56% |
Simplify (9a)(4ab) + (7a2)(5b).
| 71ab2 | |
| 71a2b | |
| 156ab2 | |
| a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(9a)(4ab) + (7a2)(5b)
(9 x 4)(a x a x b) + (7 x 5)(a2 x b)
(36)(a1+1 x b) + (35)(a2b)
36a2b + 35a2b
71a2b
Solve 9c - 5c = -2c + 4z + 4 for c in terms of z.
| \(\frac{9}{11}\)z + \(\frac{4}{11}\) | |
| -\(\frac{1}{2}\)z + \(\frac{3}{4}\) | |
| 1\(\frac{1}{6}\)z - \(\frac{1}{6}\) | |
| 5\(\frac{1}{2}\)z + 4 |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
9c - 5z = -2c + 4z + 4
9c = -2c + 4z + 4 + 5z
9c + 2c = 4z + 4 + 5z
11c = 9z + 4
c = \( \frac{9z + 4}{11} \)
c = \( \frac{9z}{11} \) + \( \frac{4}{11} \)
c = \(\frac{9}{11}\)z + \(\frac{4}{11}\)
If the base of this triangle is 7 and the height is 2, what is the area?
| 65 | |
| 7 | |
| 78 | |
| 91 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 7 x 2 = \( \frac{14}{2} \) = 7
What is 8a3 - 4a3?
| 4a3 | |
| a36 | |
| 12a6 | |
| 4 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
8a3 - 4a3 = 4a3
Which of the following statements about a parallelogram is not true?
the perimeter of a parallelogram is the sum of the lengths of all sides |
|
opposite sides and adjacent angles are equal |
|
a parallelogram is a quadrilateral |
|
the area of a parallelogram is base x height |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).