| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.15 |
| Score | 0% | 63% |
If c = 6 and x = -2, what is the value of 5c(c - x)?
| -64 | |
| 14 | |
| 312 | |
| 240 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
5c(c - x)
5(6)(6 + 2)
5(6)(8)
(30)(8)
240
If side a = 4, side b = 1, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{17} \) | |
| \( \sqrt{145} \) | |
| \( \sqrt{85} \) | |
| \( \sqrt{26} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 42 + 12
c2 = 16 + 1
c2 = 17
c = \( \sqrt{17} \)
Which of the following statements about math operations is incorrect?
you can add monomials that have the same variable and the same exponent |
|
all of these statements are correct |
|
you can multiply monomials that have different variables and different exponents |
|
you can subtract monomials that have the same variable and the same exponent |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?
2lw x 2wh + 2lh |
|
h2 x l2 x w2 |
|
h x l x w |
|
lw x wh + lh |
A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.
Solve for x:
-4x + 5 < \( \frac{x}{-1} \)
| x < -\(\frac{21}{41}\) | |
| x < 1\(\frac{10}{71}\) | |
| x < \(\frac{36}{71}\) | |
| x < 1\(\frac{2}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-4x + 5 < \( \frac{x}{-1} \)
-1 x (-4x + 5) < x
(-1 x -4x) + (-1 x 5) < x
4x - 5 < x
4x - 5 - x < 0
4x - x < 5
3x < 5
x < \( \frac{5}{3} \)
x < 1\(\frac{2}{3}\)