When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 7c + 6c = 4c + 2z - 2 for c in terms of z.
| 2z - 1\(\frac{3}{5}\) | |
| -1\(\frac{1}{3}\)z - \(\frac{2}{3}\) | |
| 3z - 1 | |
| -\(\frac{1}{3}\)z - 2\(\frac{1}{3}\) |