| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.15 |
| Score | 0% | 63% |
Which of the following expressions contains exactly two terms?
polynomial |
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binomial |
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quadratic |
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monomial |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.
Solve for y:
-8y - 2 < -5 + 4y
| y < -1\(\frac{1}{5}\) | |
| y < -4 | |
| y < \(\frac{1}{4}\) | |
| y < \(\frac{8}{9}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-8y - 2 < -5 + 4y
-8y < -5 + 4y + 2
-8y - 4y < -5 + 2
-12y < -3
y < \( \frac{-3}{-12} \)
y < \(\frac{1}{4}\)
For this diagram, the Pythagorean theorem states that b2 = ?
c2 - a2 |
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a2 - c2 |
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c2 + a2 |
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c - a |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
Factor y2 - y - 20
| (y - 5)(y - 4) | |
| (y + 5)(y + 4) | |
| (y - 5)(y + 4) | |
| (y + 5)(y - 4) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -20 as well and sum (Inside, Outside) to equal -1. For this problem, those two numbers are -5 and 4. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - y - 20
y2 + (-5 + 4)y + (-5 x 4)
(y - 5)(y + 4)
If BD = 28 and AD = 29, AB = ?
| 6 | |
| 1 | |
| 5 | |
| 7 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BD