When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve a - 3a = 4a + 8y + 6 for a in terms of y.
| -\(\frac{5}{6}\)y + 1\(\frac{1}{2}\) | |
| 1\(\frac{1}{6}\)y + 1\(\frac{1}{6}\) | |
| -4\(\frac{1}{3}\)y - 1 | |
| -3\(\frac{2}{3}\)y - 2 |