ASVAB Math Knowledge Practice Test 536601

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -2a - 6a = 2a + 7z - 1 for a in terms of z.

z - \(\frac{1}{7}\)
-3\(\frac{1}{4}\)z + \(\frac{1}{4}\)
1\(\frac{1}{2}\)z + 4\(\frac{1}{2}\)
\(\frac{1}{13}\)z + \(\frac{5}{13}\)