ASVAB Math Knowledge Practice Test 538625

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -7a + 6a = 3a + 7y - 3 for a in terms of y.

\(\frac{10}{13}\)y + \(\frac{6}{13}\)
-\(\frac{1}{2}\)y - \(\frac{2}{9}\)
y + \(\frac{9}{14}\)
-\(\frac{1}{10}\)y + \(\frac{3}{10}\)