ASVAB Math Knowledge Practice Test 538679 Results

Your Results Global Average
Questions 5 5
Correct 0 3.24
Score 0% 65%

Review

1

If side x = 6cm, side y = 7cm, and side z = 8cm what is the perimeter of this triangle?

84% Answer Correctly
21cm
32cm
34cm
31cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 6cm + 7cm + 8cm = 21cm


2

The dimensions of this cube are height (h) = 3, length (l) = 3, and width (w) = 1. What is the surface area?

51% Answer Correctly
42
286
30
76

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 3 x 1) + (2 x 1 x 3) + (2 x 3 x 3)
sa = (6) + (6) + (18)
sa = 30


3

The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?

67% Answer Correctly

h2 x l2 x w2

lw x wh + lh

h x l x w

2lw x 2wh + 2lh


Solution

A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.


4

This diagram represents two parallel lines with a transversal. If b° = 143, what is the value of w°?

73% Answer Correctly
37
152
15
140

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with b° = 143, the value of w° is 37.


5

The dimensions of this cylinder are height (h) = 1 and radius (r) = 4. What is the surface area?

48% Answer Correctly
40π
120π
84π
88π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(42) + 2π(4 x 1)
sa = 2π(16) + 2π(4)
sa = (2 x 16)π + (2 x 4)π
sa = 32π + 8π
sa = 40π