ASVAB Math Knowledge Practice Test 538930

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -2b - 2b = 5b - z + 1 for b in terms of z.

-\(\frac{1}{5}\)z - \(\frac{7}{15}\)
-6z + 2\(\frac{1}{2}\)
-\(\frac{1}{7}\)z - \(\frac{1}{7}\)
-1\(\frac{4}{9}\)z - \(\frac{1}{3}\)