When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 8c = -6c + 5x + 2 for c in terms of x.
| -\(\frac{5}{6}\)x + \(\frac{5}{6}\) | |
| -\(\frac{3}{10}\)x + \(\frac{1}{5}\) | |
| 12x + 8 | |
| -2\(\frac{2}{3}\)x - 2 |