ASVAB Math Knowledge Practice Test 540216

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 8c - 4c = -2c + 7y - 8 for c in terms of y.

1\(\frac{1}{10}\)y - \(\frac{4}{5}\)
\(\frac{1}{7}\)y + \(\frac{1}{7}\)
\(\frac{1}{7}\)y + 1\(\frac{2}{7}\)
-4y + 4\(\frac{1}{2}\)