ASVAB Math Knowledge Practice Test 540250 Results

Your Results Global Average
Questions 5 5
Correct 0 2.68
Score 0% 54%

Review

1

Simplify (6a)(5ab) - (9a2)(7b).

62% Answer Correctly
-33a2b
93a2b
176ab2
93ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(5ab) - (9a2)(7b)
(6 x 5)(a x a x b) - (9 x 7)(a2 x b)
(30)(a1+1 x b) - (63)(a2b)
30a2b - 63a2b
-33a2b


2

If a = c = 4, b = d = 8, and the blue angle = 60°, what is the area of this parallelogram?

66% Answer Correctly
32
45
8
6

Solution

The area of a parallelogram is equal to its length x width:

a = l x w
a = a x b
a = 4 x 8
a = 32


3

On this circle, line segment CD is the:

46% Answer Correctly

diameter

radius

chord

circumference


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


4

Solve for a:
a2 + 8a + 21 = -a + 1

48% Answer Correctly
8 or 4
7 or 4
3 or -8
-4 or -5

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

a2 + 8a + 21 = -a + 1
a2 + 8a + 21 - 1 = -a
a2 + 8a + a + 20 = 0
a2 + 9a + 20 = 0

Next, factor the quadratic equation:

a2 + 9a + 20 = 0
(a + 4)(a + 5) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (a + 4) or (a + 5) must equal zero:

If (a + 4) = 0, a must equal -4
If (a + 5) = 0, a must equal -5

So the solution is that a = -4 or -5


5

Solve for c:
-5c - 1 = \( \frac{c}{2} \)

46% Answer Correctly
\(\frac{48}{55}\)
-\(\frac{2}{11}\)
-7
-\(\frac{3}{17}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-5c - 1 = \( \frac{c}{2} \)
2 x (-5c - 1) = c
(2 x -5c) + (2 x -1) = c
-10c - 2 = c
-10c - 2 - c = 0
-10c - c = 2
-11c = 2
c = \( \frac{2}{-11} \)
c = -\(\frac{2}{11}\)