| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.92 |
| Score | 0% | 58% |
Solve 8c - 8c = -4c - 8z - 5 for c in terms of z.
| z - \(\frac{5}{12}\) | |
| -3z - 6 | |
| \(\frac{7}{10}\)z - \(\frac{7}{10}\) | |
| \(\frac{1}{3}\)z + \(\frac{2}{3}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
8c - 8z = -4c - 8z - 5
8c = -4c - 8z - 5 + 8z
8c + 4c = -8z - 5 + 8z
12c = - 5
c = \( \frac{ - 5}{12} \)
c = \( \frac{}{12} \) + \( \frac{-5}{12} \)
c = z - \(\frac{5}{12}\)
A right angle measures:
360° |
|
45° |
|
180° |
|
90° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.
The dimensions of this trapezoid are a = 6, b = 5, c = 7, d = 7, and h = 5. What is the area?
| 10\(\frac{1}{2}\) | |
| 21 | |
| 30 | |
| 10 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(5 + 7)(5)
a = ½(12)(5)
a = ½(60) = \( \frac{60}{2} \)
a = 30
If angle a = 53° and angle b = 51° what is the length of angle d?
| 130° | |
| 127° | |
| 136° | |
| 115° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 53° - 51° = 76°
So, d° = 51° + 76° = 127°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 53° = 127°
If the base of this triangle is 4 and the height is 4, what is the area?
| 12\(\frac{1}{2}\) | |
| 49\(\frac{1}{2}\) | |
| 97\(\frac{1}{2}\) | |
| 8 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 4 x 4 = \( \frac{16}{2} \) = 8