ASVAB Math Knowledge Practice Test 541314

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -9a + 8a = -6a + 4x + 5 for a in terms of x.

x + \(\frac{3}{10}\)
1\(\frac{1}{3}\)x - 1\(\frac{2}{3}\)
1\(\frac{5}{6}\)x - \(\frac{1}{2}\)
-\(\frac{15}{16}\)x + \(\frac{3}{16}\)