ASVAB Math Knowledge Practice Test 541566 Results

Your Results Global Average
Questions 5 5
Correct 0 2.97
Score 0% 59%

Review

1

If the base of this triangle is 1 and the height is 1, what is the area?

58% Answer Correctly
65
\(\frac{1}{2}\)
31\(\frac{1}{2}\)
27

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 1 x 1 = \( \frac{1}{2} \) = \(\frac{1}{2}\)


2

Find the value of c:
-3c + y = -4
-6c - 5y = 5

42% Answer Correctly
\(\frac{13}{14}\)
-1\(\frac{8}{25}\)
-\(\frac{4}{23}\)
\(\frac{5}{7}\)

Solution

You need to find the value of c so solve the first equation in terms of y:

-3c + y = -4
y = -4 + 3c

then substitute the result (-4 - -3c) into the second equation:

-6c - 5(-4 + 3c) = 5
-6c + (-5 x -4) + (-5 x 3c) = 5
-6c + 20 - 15c = 5
-6c - 15c = 5 - 20
-21c = -15
c = \( \frac{-15}{-21} \)
c = \(\frac{5}{7}\)


3

A(n) __________ is two expressions separated by an equal sign.

77% Answer Correctly

problem

formula

equation

expression


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


4

Factor y2 - 3y - 10

54% Answer Correctly
(y + 5)(y + 2)
(y - 5)(y + 2)
(y + 5)(y - 2)
(y - 5)(y - 2)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -10 as well and sum (Inside, Outside) to equal -3. For this problem, those two numbers are -5 and 2. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 - 3y - 10
y2 + (-5 + 2)y + (-5 x 2)
(y - 5)(y + 2)


5

If side a = 7, side b = 1, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{128} \)
\( \sqrt{89} \)
\( \sqrt{50} \)
10

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 72 + 12
c2 = 49 + 1
c2 = 50
c = \( \sqrt{50} \)