ASVAB Math Knowledge Practice Test 542142

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5c - 7c = 6c - 6z - 2 for c in terms of z.

z - 3
-z + 2
3z - \(\frac{1}{2}\)
-\(\frac{1}{5}\)z - 1\(\frac{4}{5}\)