ASVAB Math Knowledge Practice Test 54411

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -3b + 3b = -7b + 5z - 1 for b in terms of z.

-1\(\frac{1}{5}\)z + 1\(\frac{3}{5}\)
\(\frac{1}{18}\)z - \(\frac{1}{6}\)
\(\frac{1}{2}\)z - \(\frac{1}{4}\)
z - 4