ASVAB Math Knowledge Practice Test 544560

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5a - a = 2a + 7z + 1 for a in terms of z.

-1\(\frac{1}{16}\)z - \(\frac{1}{16}\)
-\(\frac{2}{9}\)z - \(\frac{1}{9}\)
-\(\frac{1}{5}\)z + \(\frac{4}{5}\)
2\(\frac{2}{3}\)z + \(\frac{1}{3}\)